q0

P So , to go from Q0 to Q1 we need to cross P at some place .

从Q0到Q1，我们必须经过平面上某点。

To analyze the concentration of coenzyme Q0 in oxidation reaction mixture by HPLC , and then to determine the reaction end point .

利用反相HPLC法监控氧化反应中辅酶Q0的含量，从而确定氧化反应终点。

Let 's imagine that we have a point that 's moving on the line , and at time zero , it 's here at Q0 .

我们可以想像由一个在直线上移动的点，在时刻0的时候，它在Q0处。

This is the vector from Q0 to Q.

这是由Q0指向Q的向量。

So , let 's say Q is a moving point , Q0 and at t = 0 it 's at Q0 .

因此我们说Q，是一个运动着的点，当t=0时，它在。

The synthesis of coenzyme Q0 started from p-Cresol by a sequence of reactions including bromination , methoxylation , hydroxy-methylation and oxidation .

以对甲酚为起始原料，经溴化、甲氧基化、羟甲基化和氧化反应得到了辅酶Q0。

This point , Q0 and Q1 , are they on the same side , on opposite sides , is one of them on the plane , or we can 't decide ?

点Q0和Q1，在它的同侧还是异侧？，或者其中一个在平面上，抑或是不能确定？

You cannot get20 outputs without adding more hardware because of the fact that , upon powering up , each CD4017 counter displays output Q0 as being on .

由于供电后每个CD4017计数器的输出Q0都工作，所以不能在没有增加硬件的情况下得到20输出。

Well , to answer that we have an easy observation , which is that the vector from Q0 to Q of t is proportional to the vector from Q0 to Q1 .

为了回答这个问题，我们观察可以知道，由Q0指向Q的那个向量，和由Q0指向Q1的向量成比例。

The ratio Qc / Q0 is much less influenced by the aerosol , surface altitude and cloud altitude and therefore is a adoptable parameter representing the influence of the cloud on the global radiation at the earth 's surface .

比值Qc/Qo受气溶胶、海拔高度、云的高度的影响很小，可作为表示云对地面总辐射影响的一个参数。

The separation degree of the curves reflected the relative specific degradation rate of substrate ( q / q0 ) and the relative specific growth rate of sludge (μ / μ 0 ) increased with the varying of the concentration of DCP ;

相对底物比降解速率（q/q0）和相对污泥比增长速率（μ/0μ）随DCP浓度变化曲线分离程度增加；

Q1 Now , we know not only the points Q0 and Q1 , we know actually any point on the line because we have a parametric equation up there telling us , where is the point that 's moving on the line at time t ?

现在，我们不仅知道Q0和，实际上我们知道直线上左右的点，因为参数方程告诉了我们这一切，告诉了我们时刻t的时候，点在何处？

So , OK , so apart from that , I claim now we can find the position of its moving point Q0Q1 because , well , this vector , Q0Q1 we can find from the coordinates of Q0 and Q1 .

不管那些了，我断言我们可以找出移动点的位置了，因为对于向量1，我们可以找出Q0和Q1的坐标。